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0=2+25.5x-4.9x^2
We move all terms to the left:
0-(2+25.5x-4.9x^2)=0
We add all the numbers together, and all the variables
-(2+25.5x-4.9x^2)=0
We get rid of parentheses
4.9x^2-25.5x-2=0
a = 4.9; b = -25.5; c = -2;
Δ = b2-4ac
Δ = -25.52-4·4.9·(-2)
Δ = 689.45
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-25.5)-\sqrt{689.45}}{2*4.9}=\frac{25.5-\sqrt{689.45}}{9.8} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-25.5)+\sqrt{689.45}}{2*4.9}=\frac{25.5+\sqrt{689.45}}{9.8} $
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